Samsung 30Q / Lg HG2 in series for a 200w mod

[RedLabel]

Hello, please help me to chose a longer life battery for my mods.

I have a Wismec Rx200 with 3x18650 in series and smok H-Priv 220w with 2x18650 in series too.

Actualy i`m using some VTC4 and VTC5 bought for a China vendor and i want more battery life.

I`m using some rta atomizers with dual kanthal claptons wich have final resistance at 0.2 -0.6 ohm.
I`m vaping at 50w-80w maximum.

VTC4 has 2100 mAh and VTC5 has 2600mAh and i realised that VTC5 long a little bit longer (not much).

As i`m not using to many wattage i need more battery life and maybe i can use some highter mAh battery for longer life.

I found those Samsung 30Q on Gearbest (18$ for 4 pack) and they are in the same range with LG HG2.

Are those more safe in 3x18650 series than 2x18650 series?

I don`t know if they are genuine but what i want to ask is if is safe to use those kind of batteries and they will last more than my VTC4/5 for my setups .

Sincere thanks.

 

[rice721]

Yes I use the 30Q and HG2 in dual series mods.

 

[RedLabel]

At what wattage do you vape usualy?
Did you comparred them with VTC4/5 ?
Thank you

 

[RedLabel]

How should i calculate Ohm law with 2 batteries in series on a regulated mod?

I=V/R .... V = 3.7 or i should double it for 2 batteries in series in a regulated mod ???

For example:
R=0.18 ohms ....

I=3.7 / 0.18
or
I=7.4 / 0.18

Thank you.

 

[rice721]

At what wattage do you vape usualy?
Did you comparred them with VTC4/5 ?
Thank you

I also have a married set of VTC5s. The LG HG2s last a tad longer. I normally vape around 30-60 depending on build.

How should i calculate Ohm law with 2 batteries in series on a regulated mod?

I=V/R .... V = 3.7 or i should double it for 2 batteries in series in a regulated mod ???

For example:
R=0.18 ohms ....

I=3.7 / 0.18
or
I=7.4 / 0.18

Thank you.

For regulated devices you're not going to need resistance in your calculation bc unlike in a mechanical mod, your board dictates the power going into your coils.

In series, yes, you double the nominal voltage.

So 2 batteries in series yield 7.4 nominal voltage. Assuming a 90% efficient chip you're left with 6.66V

To get the Amperage (CDR) required just divide the power you vape at: expample 120W by 6.66V

So it would be 18Amps

The equation is Amperage required = Power (in Watts) / Volts or A = P / V


Basically with regulated mods I keep my power level under 60W per 20A battery. So single battery mod is 60W, dual is 120W max, etc etc.

 

[RedLabel]

Thank you !!!

I made some tests with 3 atomizers of mine.....with resistences of 0.3, 0.37 and 0.43 ohm (kanthal) using Joyetech Cuboid mod with 2 x VTC5.

At 0.3 ohm at 150 w i had (on screen display) 6.71v and 20.1 A !!!

I attached PDF here.

I bought a Smok RDTA (not received yet) wich has 0.18ohm and i want to ask you if you can figure at 120w , what amperage will it has.

Thank you.

 

[Mooch]

How should i calculate Ohm law with 2 batteries in series on a regulated mod?

I=V/R .... V = 3.7 or i should double it for 2 batteries in series in a regulated mod ???

For example:
R=0.18 ohms ....

I=3.7 / 0.18
or
I=7.4 / 0.18

Thank you.

This might help...
Calculating battery current draw for a regulated mod | E-Cigarette Forum

For the HG2/30Q a limit of 60W-75W per battery is about right.

 

[RedLabel]

Awsome!!!

A lot of people vape at 0.3-0.4 ohm with 50-70w on a dual batteries regulated mods and they use super high drain batteries with 1800-2100 mAh BUT they never use high battery efficiency and they have to buy and change a lot o batteries....

You made me saving a lot of vaping time using those 3000 mAh vs 2100 mAh !!!

Thank you very much!!!

 

[rice721]

Awsome!!!

A lot of people vape at 0.3-0.4 ohm with 50-70w on a dual batteries regulated mods and they use super high drain batteries with 1800-2100 mAh BUT they never use high battery efficiency and they have to buy and change a lot o batteries....

You made me saving a lot of vaping time using those 3000 mAh vs 2100 mAh !!!

Thank you very much!!!

yep, 60W per 20A CDR battery in a regulated mod is very very safe IMHO, that is exactly why you see dual 18650 DNA200 mods advertising itself as max 133W.

 

[KenD]

For regulated devices you're not going to need resistance in your calculation bc unlike in a mechanical mod, your board dictates the power going into your coils.

In series, yes, you double the nominal voltage.

So 2 batteries in series yield 7.4 nominal voltage. Assuming a 90% efficient chip you're left with 6.66V

To get the Amperage (CDR) required just divide the power you vape at: expample 120W by 6.66V

So it would be 18Amps

The equation is Amperage required = Power (in Watts) / Volts or A = P / V


Basically with regulated mods I keep my power level under 60W per 20A battery. So single battery mod is 60W, dual is 120W max, etc etc.

True, but you need to use the low voltage cutoff instead of the nominal voltage when calculating max amp draw.

Sent from my M7_PLUS using Tapatalk

 

[KenD]

At 0.3 ohm at 150 w i had (on screen display) 6.71v and 20.1 A !!!

Most mods (all that I know of in fact) that show amps display the amp load at the atomizer, not the amp draw at the battery. Amp load at the atomizer is practically useless information.

Sent from my M7_PLUS using Tapatalk

 

[rice721]

True, but you need to use the low voltage cutoff instead of the nominal voltage when calculating max amp draw.

Sent from my M7_PLUS using Tapatalk

Indeed, but I've noticed that there is no standard for the "soft cut-off" on most of my regulated mods but 3.2V seems to be reasonable.

Even then 3.2v x 2 = 6.4V assuming 90% efficiency = 5.76V, so with a 20A CDR battery you're safe to do about 101.52W or 55.76W per battery. 60W is still reasonable.

 

[erikbal]

I run vtc5s and HG2's in my rx200 and do get a bit better life with the LG's. I run anywhere from .15 at 100w to .5 at 45w.

Sent from my VS980 4G using Tapatalk