Ok, I'm new to vaping, but not so new to electrics.
Here's what I know, and how I think it fits together. If you see anything that seems incorrect or inconsistent, by all means call me out!
I'm writing this because in all the threads I've read, there's one thing missing: How power (wattage) is APPLIED to the e-liquid.
First, the equations. Thank you Mr. Watt and Mr. Ohm.
"Ohm's Law" -
V = I x R
aka, Voltage = Current x Resistance
aka, Volts = Amps x Ohms
"Watt's Law" -
P = V x I
aka, Power = Voltage x Amperage
aka, Watts = Volts x Amps
Combine the two laws, and the result is:
P = V x ( V / R )
aka P = V^2 / R
aka Power = Voltage-squared divided by Resistance
aka Watts = Volts-squared divided by Ohms
All very nice and neat.
Now apply it to a wick:
If you use a short piece of fat wire, the resistance will be very low. There's very little length for the voltage to have to push its way through, and the "pipe" is plenty wide.
If you use a longer wire, or a thinner one, there's more length to push through, and a narrower cross-section to push through. Thus more resistance. And if the resistance goes up, the power (wattage) goes down (for a constant voltage).
Less power means less vapor. So why on earth would we want anything other than short little fat wires? That would offer the lowest resistance, right? And thus the highest power, right?
Well, sure, but it's only applied to a very small amount of e-liquid. So unless your wick is, well, "wicking" very very well, you're going to dry up and be heating, well... nothing, with all that power.
So, it's a trade-off. We want to heat a lot of liquid to get a lot of vapor. We also want to heat it quickly, and to a sufficient temperature.
So what's the answer? Make a longer, fatter wire that contacts more e-liquid. Longer means higher resistance, fatter means lower. Compensate for any higher resistance by stepping up the voltage, and thus the power.
Now, how does a double-wick fit in? Well, the two resistance wires are usually wired in parallel. This actually equates to the same behavior as one thicker wire, and thus less resistance. So, with the same voltage, you're putting more power to the e-liquid.
So, now that we have a plan for low ohms and high watts... we have to worry about amps. Basically, if we do too good a job at creating high power, we can overdraw the battery. Just be careful. if you're going to go the high power route, stick with high quality, high draw batteries, and use some sort of thermal protection, be it an IMR battery, a mod with protection built in, or something like a short-stop.
Clear as mud?
Here's what I know, and how I think it fits together. If you see anything that seems incorrect or inconsistent, by all means call me out!
I'm writing this because in all the threads I've read, there's one thing missing: How power (wattage) is APPLIED to the e-liquid.
First, the equations. Thank you Mr. Watt and Mr. Ohm.
"Ohm's Law" -
V = I x R
aka, Voltage = Current x Resistance
aka, Volts = Amps x Ohms
"Watt's Law" -
P = V x I
aka, Power = Voltage x Amperage
aka, Watts = Volts x Amps
Combine the two laws, and the result is:
P = V x ( V / R )
aka P = V^2 / R
aka Power = Voltage-squared divided by Resistance
aka Watts = Volts-squared divided by Ohms
All very nice and neat.
Now apply it to a wick:
If you use a short piece of fat wire, the resistance will be very low. There's very little length for the voltage to have to push its way through, and the "pipe" is plenty wide.
If you use a longer wire, or a thinner one, there's more length to push through, and a narrower cross-section to push through. Thus more resistance. And if the resistance goes up, the power (wattage) goes down (for a constant voltage).
Less power means less vapor. So why on earth would we want anything other than short little fat wires? That would offer the lowest resistance, right? And thus the highest power, right?
Well, sure, but it's only applied to a very small amount of e-liquid. So unless your wick is, well, "wicking" very very well, you're going to dry up and be heating, well... nothing, with all that power.
So, it's a trade-off. We want to heat a lot of liquid to get a lot of vapor. We also want to heat it quickly, and to a sufficient temperature.
So what's the answer? Make a longer, fatter wire that contacts more e-liquid. Longer means higher resistance, fatter means lower. Compensate for any higher resistance by stepping up the voltage, and thus the power.
Now, how does a double-wick fit in? Well, the two resistance wires are usually wired in parallel. This actually equates to the same behavior as one thicker wire, and thus less resistance. So, with the same voltage, you're putting more power to the e-liquid.
So, now that we have a plan for low ohms and high watts... we have to worry about amps. Basically, if we do too good a job at creating high power, we can overdraw the battery. Just be careful. if you're going to go the high power route, stick with high quality, high draw batteries, and use some sort of thermal protection, be it an IMR battery, a mod with protection built in, or something like a short-stop.
Clear as mud?